- #1

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x^2-2xy+y^2+5x+5y=0

using the formulas b^2-4ac=0 (indicates a parabola)

b^2-4ac<0 (indicates an ellipse)

b^2-4ac>0 (indicates a hyperbola)

2^2-4(1)(1)=0

4-4=0 therefore this graph must be a parabola!

Am I correct?

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- Thread starter TonyC
- Start date

- #1

- 86

- 0

x^2-2xy+y^2+5x+5y=0

using the formulas b^2-4ac=0 (indicates a parabola)

b^2-4ac<0 (indicates an ellipse)

b^2-4ac>0 (indicates a hyperbola)

2^2-4(1)(1)=0

4-4=0 therefore this graph must be a parabola!

Am I correct?

- #2

TD

Homework Helper

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It's indeed a parabola

- #3

- 86

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YIPPEE, thank

- #4

arildno

Science Advisor

Homework Helper

Gold Member

Dearly Missed

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[tex](x-y)^{2}+5(x+y)=0[/tex]

This can be brought onto the form:

[tex]u=-\frac{\sqrt{2}}{5}v^{2}, u=\frac{x+y}{\sqrt{2}}, v=\frac{x-y}{\sqrt{2}}[/tex]

where the u-v axes are 45 degrees rotated with respect to the xy axes.

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